(x+3)^2=5/20

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Solution for (x+3)^2=5/20 equation: 


x in (-oo:+oo)

(x+3)^2 = 5/20 // - 5/20

(x+3)^2-(5/20) = 0

(x+3)^2-1/4 = 0

(4*(x+3)^2)/4-1/4 = 0

4*(x+3)^2-1 = 0

4*x^2+24*x+35 = 0

4*x^2+24*x+35 = 0

4*x^2+24*x+35 = 0

DELTA = 24^2-(4*4*35)

DELTA = 16

DELTA > 0

x = (16^(1/2)-24)/(2*4) or x = (-16^(1/2)-24)/(2*4)

x = -5/2 or x = -7/2

(x+7/2)*(x+5/2) = 0

((x+7/2)*(x+5/2))/4 = 0

((x+7/2)*(x+5/2))/4 = 0 // * 4

(x+7/2)*(x+5/2) = 0

( x+5/2 )

x+5/2 = 0 // - 5/2

x = -5/2

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

x in { -5/2, -7/2 }

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